"sdv" <foo@bar.com> wrote
> I want to hold data from structures in another array, modify the external
> structures so that the array still refelects the changes: I''ve done as
> shown underneath but am i storing a ''reference'' in the c/c++sense or am I
> duplicating data in the ''stuff'' object? I dont wont to excessive memory
> usage.
>
> def main
> stuff=Hash::new()
> a1=[''a'',''b'',''c'']
> b1=[''a'',''d'',''f'']
> ll=nil
>
> [''a'',''b'',''c'',''d'',''e'',''f''].each {|i|
> stuff[i]=Array::new()
> }
>
> stuff[''a''].push(a1)
> stuff[''a''].push(b1)
> puts "#{stuff[''a'']}"
> a1[0]=''foo''
> puts "#{stuff[''a'']}"
> end
>
> main
stuff=Hash[]
a1=[''a'',''b'',''c'']
b1=[''a'',''d'',''f'']
[''a'',''b'',''c'',''d'',''e'',''f''].each {|i|
stuff[i]=Array::new()
}
stuff[''a''].push(a1)
stuff[''a''].push(b1)
p stuff[''a'']
a1[0]=''foo''
p stuff[''a'']
a1.size.times do |ix|
p [ a1[ix], stuff[''a''][0][ix] ]
puts ''OK'' if a1[ix].object_id == stuff[''a''][0][ix].object_id
end
#-> [["a", "b", "c"], ["a", "d", "f"]]
#-> [["foo", "b", "c"], ["a", "d", "f"]]
#-> ["foo", "foo"]
#-> OK
#-> ["b", "b"]
#-> OK
#-> ["c", "c"]
#-> OK
Comparing object_id shows whether or not you''re referring to
the same objects.
In your example, you are.
daz