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comp.lang.python

How to parse this timestamp?

Roy Smith

3/12/2008 10:16:00 PM

I've got timestamps in a file that look like:

[19-Aug-2007 07:38:43+216ms NZST]

How can I parse them? I don't see any way to build a strftime()
format string that can handle the +216ms part. The best I can see is
tearing it all apart with a regex, but I'm trying to avoid that pain
if I can.

(PS: I have no clue why google groups thinks it should put
"gnu.gcc.help" on the from line)
2 Answers

Miki

3/12/2008 10:31:00 PM

0

Hello,

> [19-Aug-2007 07:38:43+216ms NZST]
>
> How can I parse them?  I don't see any way to build a strftime()
> format string that can handle the +216ms part. The best I can see is
> tearing it all apart with a regex, but I'm trying to avoid that pain
> if I can.
>
> (PS: I have no clue why google groups thinks it should put
> "gnu.gcc.help" on the from line)
Just zap the end and use time.strptime:
>>> s = '19-Aug-2007 07:38:43+216ms NZST'
>>> strptime(re.sub("\+\d{3}ms [A-Z]{4}", "", s), "%d-%b-%Y %H:%M:%S")
(2007, 8, 19, 7, 38, 43, 6, 231, -1)
>>>

HTH,
--
Miki <miki.tebeka@gmail.com>
http://pythonwise.bl...

Diez B. Roggisch

3/12/2008 10:32:00 PM

0

gnu.gcc.help schrieb:
> I've got timestamps in a file that look like:
>
> [19-Aug-2007 07:38:43+216ms NZST]
>
> How can I parse them? I don't see any way to build a strftime()
> format string that can handle the +216ms part. The best I can see is
> tearing it all apart with a regex, but I'm trying to avoid that pain
> if I can.
>
> (PS: I have no clue why google groups thinks it should put
> "gnu.gcc.help" on the from line)
>
Then don't use the regexes. Use string.split to separate the string on
the +, then parse the left part with strptime, and usp pytz and
datetime.timedelta to do the rest.

Diez