GHUM
3/12/2008 10:14:00 AM
Farsheed Ashouri ,
> Here is my script
> #**********************************************************************
> #**********************************************************************
> import threading
> import socket
> def openSocket(portNum):
> mySocket = socket.socket ( socket.AF_INET, socket.SOCK_STREAM )
> mySocket.bind ( ( '', portNum ) )
> mySocket.listen ( 1 )
> channel, details = mySocket.accept()
> msg = channel.recv(4096)
>
> class CmdPortThread( threading.Thread ):
> def run( self ):
> openSocket(6000)
>
> def fakeCommandPort():
> CmdPortThread().start()
> fakeCommandPort()
> If works perfect with python 2.5.2. Now I want to convert it to
> standalone program.
> but the .exe file fails to run without any error.
are you sure that it fails to run? I expect it to run, and exit
immediately after fakeCommandPort(). That is: there is nothing more to
do in the main thread, so the application exits.
To learn more, add prints and use the usual if __name__=='__main__'
class CmdPortThread( threading.Thread ):
def run( self ):
print "Thread CmdPortThread running"
openSocket(6000)
if __name__=='__main__':
print "Mese running"
fakeCommandPort()
print "Mese done starting Thread"
Harald