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comp.lang.ruby

change (and update) values of hash

Jason

3/12/2009 5:40:00 AM

how would I do stuff to each value of a hash and return a modified hash?
h = {"a"=> 3, "b"=> 5}
multiply each value by 2 and return
h = {"a"=> 6, "b"=> 10}

this does what I need but does not modify the hash

h.each {|k,v| h[k]*2}
--
Posted via http://www.ruby-....
7 Answers

Jason

3/12/2009 5:50:00 AM

0

Is this the best solution:

h = {"a"=> 3, "b"=> 5}

x = {}

h.each {|k,v| x[k] = v*2}

=> {"a"=>3, "b"=>5}

h.replace(x)

=> {"a"=>6, "b"=>10}


?
--
Posted via http://www.ruby-....

lasitha

3/12/2009 6:08:00 AM

0

On Thu, Mar 12, 2009 at 11:10 AM, Jason Lillywhite
<jason.lillywhite@gmail.com> wrote:
> how would I do stuff to each value of a hash and return a modified hash?
> h = {"a"=> 3, "b"=> 5}
> multiply each value by 2 and return
> h = {"a"=> 6, "b"=> 10}

One way (among several):
$: irb
01> h = { 'a' => 3, 'b' => 5 }
--> {"a"=>3, "b"=>5}
02> h.inject(h) {|h, (k, v)| h[k] = v * 2; h }
--> {"a"=>6, "b"=>10}

solidarity,
lasitha.

lasitha

3/12/2009 6:15:00 AM

0

On Thu, Mar 12, 2009 at 11:37 AM, lasitha <lasitha.ranatunga@gmail.com> wrote:
> On Thu, Mar 12, 2009 at 11:10 AM, Jason Lillywhite
> <jason.lillywhite@gmail.com> wrote:
>> how would I do stuff to each value of a hash and return a modified hash?
>> h = {"a"=> 3, "b"=> 5}
>> multiply each value by 2 and return
>> h = {"a"=> 6, "b"=> 10}
>
> One way (among several):
> $: irb
> 01> h = { 'a' => 3, 'b' => 5 }
> --> {"a"=>3, "b"=>5}
> 02> h.inject(h) {|h, (k, v)| h[k] = v * 2; h }
> --> {"a"=>6, "b"=>10}

I'm being silly (its fun being silly with inject :).
This is much easier:
h.each {|k, v| h[k] = v * 2 }

lasitha.

Jason

3/12/2009 6:36:00 AM

0


> This is much easier:
> h.each {|k, v| h[k] = v * 2 }

thank you.

I was told it could be bad to change values during iteration. That is
why I proposed doing replace. what do you think?
--
Posted via http://www.ruby-....

lasitha

3/12/2009 7:11:00 AM

0

On Thu, Mar 12, 2009 at 12:06 PM, Jason Lillywhite
<jason.lillywhite@gmail.com> wrote:
>
>> This is much easier:
>> h.each {|k, v| h[k] = v * 2 }
>
> thank you.
>
> I was told it could be bad to change values during iteration. That is
> why I proposed doing replace. what do you think?

There was a recent thread about this:
http://www.nabble.com/Iterating-a-changing-Hash-under-1.9.1-td220...

I believe assigning values to existing keys is safe.

If in doubt, iterate over the keys instead:
h.keys.each {|k| h[k] = h[v] * 2 }

solidarity,
lasitha.

lasitha

3/12/2009 7:12:00 AM

0

On Thu, Mar 12, 2009 at 12:42 PM, lasitha <lasitha.ranatunga@gmail.com> wrote:
> If in doubt, iterate over the keys instead:
> h.keys.each {|k| h[k] = h[v] * 2 }
~~~~
oops. should be h[k] = h[k] * 2
lasitha.

Rob Biedenharn

3/12/2009 4:05:00 PM

0

On Mar 12, 2009, at 3:12 AM, lasitha wrote:

> On Thu, Mar 12, 2009 at 12:42 PM, lasitha
> <lasitha.ranatunga@gmail.com> wrote:
>> If in doubt, iterate over the keys instead:
>> h.keys.each {|k| h[k] = h[v] * 2 }
> ~~~~
> oops. should be h[k] = h[k] * 2
> lasitha.


Or use a little sugar:

h.keys.each {|k| h[k] *= 2 }


Rob Biedenharn http://agileconsult...
Rob@AgileConsultingLLC.com