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comp.lang.ruby
Net/HTTP get
Tim Mcd
2/4/2009 1:47:00 AM
doc = Hpricot(open("
http://redhanded.hobix.com/index....
))
images = (doc/"img")
count = 0
Net::HTTP.start("redhanded.hobix.com") do |http|
images.each do |img|
filename = img['src'].match(/([^\/]+\..+)/)
resp = http.get("#{img["src"]}")
open("#{filename[1]}", "w") do |file|
file.write(resp.body)
end
count += 1
end
end
So thats fairly simple, because images on _why's blog are stored as
such: redhanded.hobix.com/images/whatever.w/e
But how would I grab an image if it was, say, on slashdot.com?
(images.slashdot.com/image.jpg)
With my understanding, doing just an http.get("images.slashdot.etc.")
wouldn't work, because it bases it off of the .start? Any help is
appreciated!
--
Posted via
http://www.ruby-...
.
1 Answer
Mark Thomas
2/4/2009 2:25:00 AM
0
On Feb 3, 8:47 pm, Tim Mcd <tmcdow...@gmail.com> wrote:
> doc = Hpricot(open("
http://redhanded.hobix.com/index....
))
> images = (doc/"img")
> count = 0
>
> Net::HTTP.start("redhanded.hobix.com") do |http|
> images.each do |img|
> filename = img['src'].match(/([^\/]+\..+)/)
> resp = http.get("#{img["src"]}")
If it's a full URL then you just have to create a uri object:
http.get(URI.parse(img['src']))
- Mark.
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