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comp.lang.ruby

OptParse bug?

Roger Pack

1/31/2009 8:03:00 PM

With this file:

C:\dev\thesis_p2pwebcode\src>cat example.rb
require 'optparse'

OptionParser.new do |opts|

opts.on('-p', '--do_multiples_with_variant=NAME', 'multiples variant
ex: ') do |name|
end
end.parse!


I get the following output:
Usage: example [options]
-p=NAME multiples variant ex:
--do_multiples_with_variant


however it doesn't actually accept -p=NAME
it accepts -pNAME

Anybody know if this is expected?
Thanks!
-=r
--
Posted via http://www.ruby-....
4 Answers

Joel VanderWerf

1/31/2009 8:40:00 PM

0

Roger Pack wrote:
> With this file:
>
> C:\dev\thesis_p2pwebcode\src>cat example.rb
> require 'optparse'
>
> OptionParser.new do |opts|
>
> opts.on('-p', '--do_multiples_with_variant=NAME', 'multiples variant
> ex: ') do |name|
> end
> end.parse!
>
>
> I get the following output:
> Usage: example [options]
> -p=NAME multiples variant ex:
> --do_multiples_with_variant
>
>
> however it doesn't actually accept -p=NAME
> it accepts -pNAME
>
> Anybody know if this is expected?
> Thanks!
> -=r

Seems to be a unix standard:

http://www.faqs.org/docs/artu/ch...

--
vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407

Roger Pack

1/31/2009 10:35:00 PM

0


>
> Seems to be a unix standard:
>
> http://www.faqs.org/docs/artu/ch...

So were you saying that having help output like
"-p=NAME" is standard when the input is actually "-pNAME" in use?

OptParse typically outputs
"-p --long=NAME"

but in this case it seems to output
"-p=NAME --long"

for some reason.

Thoughts?
-=r
--
Posted via http://www.ruby-....

Joel VanderWerf

1/31/2009 10:55:00 PM

0

Roger Pack wrote:
>> Seems to be a unix standard:
>>
>> http://www.faqs.org/docs/artu/ch...
>
> So were you saying that having help output like
> "-p=NAME" is standard when the input is actually "-pNAME" in use?
>
> OptParse typically outputs
> "-p --long=NAME"
>
> but in this case it seems to output
> "-p=NAME --long"
>
> for some reason.
>
> Thoughts?
> -=r

So, both of the following are issues, right?

1. parser doesn't accept syntax "-p=NAME", but only "-pNAME"

2. generated help text suggests otherwise, that the former is accepted

IMO, #1 is standard, but #2 is possibly the wrong behavior.

What is causing the difference between typical output and this case? Do
you see the "-p --long=NAME" variant for other options in the same
program? Looking at comparable output in my own use of optparse, the
format tends to look like this:

-r, --read-options [FILE] Read options from file [stdin]

--
vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407

F. Senault

1/31/2009 11:35:00 PM

0

Le 31 janvier 2009 à 23:55, Joel VanderWerf a écrit :

> What is causing the difference between typical output and this case? Do
> you see the "-p --long=NAME" variant for other options in the same
> program? Looking at comparable output in my own use of optparse, the
> format tends to look like this:
>
> -r, --read-options [FILE] Read options from file [stdin]

It seems to be the length of the option name :

0:33 fred@ardberg:/data/ruby/blackops% irb
>> require 'optparse' ; OptionParser.new do |o|
?> o.on('-p', '--12345678901234567890=NAME',
?> 'multiples variant ex: ') {}
>> end.parse(['-h'])
Usage: irb [options]
-p, --12345678901234567890=NAME multiples variant ex:

>> require 'optparse' ; OptionParser.new do |o|
?> o.on('-p', '--123456789012345678901234567890=NAME',
?> 'multiples variant ex: ') {}
>> end.parse(['-h'])
Usage: irb [options]
-p=NAME
--123456789012345678901234567890
multiples variant ex:

When short + long + value + description are too long to hold on a single
line, optionparser tries to present it better, and it shows the bug.

Fred
--
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I didn't have to steal or have to win Well they tell me that I'm wanted
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