Dan Diebolt
9/11/2008 6:08:00 PM
[Note: parts of this message were removed to make it a legal post.]
Two successive delete_at methods will do what you ask with the c array modified:
c=[[], [], ["BRKR", "2008-09-09, 11:08:28", "ISLAND", "-200","16.1000", "3,220.00", "-1.00", "3,446.688", "-1.0704", "0.00", ""],[]]
c.delete_at(0)
c.delete_at(0)
c
Perhaps you can get the essential info you need to manipulate with this:
c.delete([])
c.flatten!
I am not precisely sure why, but you cannot successfully chain either of the these two statements:
c.delete_at(0).delete_at(0)
c.delete([]).flatten!