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comp.lang.ruby

array to string conversion

Clement Ow

6/13/2008 5:47:00 AM

Hi, I have 2 arrays(which is part of the hash):

ex = {}
ex[0] = ["xls", "ini", "20080326"]
ex[1] = ["gif", "xls", "rb"]

All i managed to convert is(using .to_s):
str[0] = "xlsini20080326"
str[1] = "gifxlsrb"

but i want to convert each array into a string, something like
str[0] = "xls,ini,20080326"
str[1] = "gif,xls,rb"

where they are seperated by a comma.. Any clean way of doin this?
--
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11 Answers

Stefano Crocco

6/13/2008 5:54:00 AM

0

On Friday 13 June 2008, Clement Ow wrote:
> Hi, I have 2 arrays(which is part of the hash):
>
> ex = {}
> ex[0] = ["xls", "ini", "20080326"]
> ex[1] = ["gif", "xls", "rb"]
>
> All i managed to convert is(using .to_s):
> str[0] = "xlsini20080326"
> str[1] = "gifxlsrb"
>
> but i want to convert each array into a string, something like
> str[0] = "xls,ini,20080326"
> str[1] = "gif,xls,rb"
>
> where they are seperated by a comma.. Any clean way of doin this?

ex[0].join ','

Stefano

Sandro Paganotti

6/13/2008 8:08:00 AM

0

[Note: parts of this message were removed to make it a legal post.]

Try this:
irb(main):004:0> ex
=> {0=>["xls", "ini", "20080326"], 1=>["gif", "xls", "rb"]}
irb(main):005:0> ex = Hash[*ex.collect{|a,b| [a,b.join(",")]}.flatten]
=> {0=>"xls,ini,20080326", 1=>"gif,xls,rb"}


Sandro

On Fri, Jun 13, 2008 at 5:53 AM, Stefano Crocco <stefano.crocco@alice.it>
wrote:

> On Friday 13 June 2008, Clement Ow wrote:
> > Hi, I have 2 arrays(which is part of the hash):
> >
> > ex = {}
> > ex[0] = ["xls", "ini", "20080326"]
> > ex[1] = ["gif", "xls", "rb"]
> >
> > All i managed to convert is(using .to_s):
> > str[0] = "xlsini20080326"
> > str[1] = "gifxlsrb"
> >
> > but i want to convert each array into a string, something like
> > str[0] = "xls,ini,20080326"
> > str[1] = "gif,xls,rb"
> >
> > where they are seperated by a comma.. Any clean way of doin this?
>
> ex[0].join ','
>
> Stefano
>
>
>


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Clement Ow

6/13/2008 8:35:00 AM

0

Sandro Paganotti wrote:
> Try this:
> irb(main):004:0> ex
> => {0=>["xls", "ini", "20080326"], 1=>["gif", "xls", "rb"]}
> irb(main):005:0> ex = Hash[*ex.collect{|a,b| [a,b.join(",")]}.flatten]
> => {0=>"xls,ini,20080326", 1=>"gif,xls,rb"}
>
>
> Sandro
>
> On Fri, Jun 13, 2008 at 5:53 AM, Stefano Crocco
> <stefano.crocco@alice.it>

It works! Thanks guys for the input! ;)
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Peña, Botp

6/13/2008 8:36:00 AM

0

From: Sandro Paganotti [mailto:sandro.paganotti@gmail.com]=20
# irb(main):004:0> ex
# =3D> {0=3D>["xls", "ini", "20080326"], 1=3D>["gif", "xls", "rb"]}
# irb(main):005:0> ex =3D Hash[*ex.collect{|a,b| =
[a,b.join(",")]}.flatten]
# =3D> {0=3D>"xls,ini,20080326", 1=3D>"gif,xls,rb"}

;)

irb(main):018:0> ex.inject({}){|h,(v,k)| h[v]=3Dk.join(",");h}
=3D> {0=3D>"xls,ini,20080326", 1=3D>"gif,xls,rb"}


kind regards -botp

alandacosta@gmail.com

6/13/2008 9:59:00 AM

0

I'm not exactly sure what's up with your hash wrapper. I think it
would be easier as an array wrapper, because indexes would be implicit
to the object, but hopefully this will do the trick; it might be the
easiest way:

ex.map {|i,v| v * "," }
=> ["xls,ini,20080326", "gif,xls,rb"]

Peña, Botp

6/13/2008 10:10:00 AM

0

From: alandacosta@gmail.com [mailto:alandacosta@gmail.com]=20
# ex.map {|i,v| v * "," }

i always forget that "*" op on arrays=20
thanks for the reminder :)

kind regards -botp

Clement Ow

6/16/2008 7:46:00 AM

0

Peña, Botp wrote:
> From: alandacosta@gmail.com [mailto:alandacosta@gmail.com]
> # ex.map {|i,v| v * "," }
>
> i always forget that "*" op on arrays
> thanks for the reminder :)
>
> kind regards -botp

Thank you guys, for your kind inputs! =) it really helped me alot!

However, I now encounter another problem..
Assuming my hash:
ex = {}
ex[0] = [".xls", ".ini", "20080326"]
ex[1] = ["RVG", ".xls", ".rb"]

I need to extract the values in each array with the extentions(values
with periods) into one string and the dir names(values without the
periods) into another string. I've been tryin to figure out but to no
avail, is there a clean way to do that?



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Peña, Botp

6/16/2008 7:51:00 AM

0

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Clement Ow

6/16/2008 8:38:00 AM

0

Peña, Botp wrote:
> From: clement.ow@asia.bnpparibas.com
> # However, I now encounter another problem..
> # Assuming my hash:
> # ex = {}
> # ex[0] = [".xls", ".ini", "20080326"]
> # ex[1] = ["RVG", ".xls", ".rb"]
> # I need to extract the values in each array with the extentions(values
> # with periods) into one string and the dir names(values without the
> # periods) into another string. I've been tryin to figure out but to no
> # avail, is there a clean way to do that?
>
> Hi Clement, pardon me because i cannot picture the problem.
> can you give an example?

Hi botp,

Assuming I have my hash:

ex = {}
ex[0] = [".xls", ".ini", "20080326"]
ex[1] = ["RVG", ".xls", ".rb"]

The result i would want:
str1 = [".xls", ".ini", ".xls", ".rb"]
str2 = ["20080326", "RVG"]

Is there any way i can do this?
Thanks.

Regards,
Clement



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Stefano Crocco

6/16/2008 8:45:00 AM

0

On Monday 16 June 2008, Clement Ow wrote:

> Hi botp,
>
> Assuming I have my hash:
>
> ex = {}
> ex[0] = [".xls", ".ini", "20080326"]
> ex[1] = ["RVG", ".xls", ".rb"]
>
> The result i would want:
> str1 = [".xls", ".ini", ".xls", ".rb"]
> str2 = ["20080326", "RVG"]
>
> Is there any way i can do this?
> Thanks.
>
> Regards,
> Clement

Try looking at Enumerable#partition. A possible way to do this is:

res = ex.values.flatten.partition{|v| v[0..0] == '.'}
p res
=> [[".xls", ".ini", ".xls", ".rb"], ["20080326", "RVG"]]

Stefano