[lnkForumImage]
TotalShareware - Download Free Software
Confronta i prezzi di migliaia di prodotti.
Asp Forum
 Home | Login | Register | Search 


 

Forums >

comp.lang.ruby

Ruby one liner killed my script

John Maclean

2/12/2008 12:05:00 AM

Talk about redundancy!

I spent some time with irb with the aim of getting an understanding of
methods and class building. I originally wanted to convert a binary
number to denary, with input from the user.

# strike one!
ruby -e 'p 0b10010101111'
does it on one line.

Anyway, I still looked at the few lines that I had and I'm wondering
how I can convert a user's input into a fixnum?


class B2d
def initialize
@ustring = " "
end

def get_bin_string
p 'binary numbers : '
@ustring = gets.chomp
end

def test_bin_string
if @ustring =~ /[a-z]|[2-9]|[A-Z]| /
p "binary digits only and no spaces, please!"
exit 1
end
end

def put_bin_string
# this is the line in which I originally tried to convert the user's
binary digit to denary puts "your bin #{@ustring.to_i} =
0b#{@ustring.to_i}" end
end

t = B2d.new
t.get_bin_string
t.test_bin_string
t.put_bin_string


--

Regards,

John Maclean


--

Regards,

John Maclean
MSc (DIC)
+44 7739 171 531
3 Answers

7stud --

2/12/2008 12:50:00 AM

0

John Maclean wrote:
> I'm wondering
> how I can convert a user's input into a fixnum?
>
> def put_bin_string
> # this is the line in which I originally tried to convert
> # the user's binary digit to denary:
>
>puts "your bin #{@ustring.to_i} =
> 0b#{@ustring.to_i}" end
> end
>

Does this help:

input = "10000001"
puts input.to_i(base=2)

--output:--
129
--
Posted via http://www.ruby-....

John Maclean

2/12/2008 1:16:00 AM

0

Where can I find out more about that method within ri?
ri Object?

On Tue, 12 Feb 2008 09:50:25 +0900
7stud -- <bbxx789_05ss@yahoo.com> wrote:

> John Maclean wrote:
> > I'm wondering
> > how I can convert a user's input into a fixnum?
> >
> > def put_bin_string
> > # this is the line in which I originally tried to convert
> > # the user's binary digit to denary:
> >
> >puts "your bin #{@ustring.to_i} =
> > 0b#{@ustring.to_i}" end
> > end
> >
>
> Does this help:
>
> input = "10000001"
> puts input.to_i(base=2)
>
> --output:--
> 129


--

Regards,

John Maclean
MSc (DIC)
+44 7739 171 531

Peña, Botp

2/12/2008 1:54:00 AM

0

From: John Maclean [mailto:info@jayeola.org]=20
# Where can I find out more about that method within ri?
# ri Object?

judging fr stud's reply, maybe you can try the string object first, eg,

botp@pc4all:~$ qri to_i
------------------------------------------------------ Multiple choices:

Class#to_i, Float#to_i, IO#to_i, IPAddr#to_i, Integer#to_i,
NilClass#to_i, Process::Status#to_i, Rational#to_i, String#to_i,
Symbol#to_i, Time#to_i

botp@pc4all:~$ qri string.to_i
------------------------------------------------------------ String#to_i
str.to_i(base=3D10) =3D> integer
------------------------------------------------------------------------
Returns the result of interpreting leading characters in str as an
integer base base (2, 8, 10, or 16). Extraneous characters past
the end of a valid number are ignored. If there is not a valid
number at the start of str, 0 is returned. This method never
raises an exception.

"12345".to_i #=3D> 12345
"99 red balloons".to_i #=3D> 99
"0a".to_i #=3D> 0
"0a".to_i(16) #=3D> 10
"hello".to_i #=3D> 0
"1100101".to_i(2) #=3D> 101
"1100101".to_i(8) #=3D> 294977
"1100101".to_i(10) #=3D> 1100101
"1100101".to_i(16) #=3D> 17826049

botp@pc4all:~$

kind regards -botp