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comp.lang.ruby

Trouble advancing date in iterator

Peter Marks

11/27/2007 11:35:00 PM

I am trying to assemble an array of month names called
"names_of_months_paid":

0 first_month_paid = client.first_month_paid
1 names_of_months_paid = []
2 number_of_months_paid.times do
3 names_of_months_paid << first_month_paid.strftime("%B")
4 first_month_paid >> (1)
5 end

For each payment ("number_of_months_paid"), I need to store the name of
the month, then store the name of the next month starting from
"first_month_paid". I seem to be having trouble advancing the month of
"first_month_paid" on line 4 as I am left with an array of first month
names. How might I get this to work?
--
Posted via http://www.ruby-....
2 Answers

Robert Dober

11/28/2007 10:52:00 AM

0

On Nov 28, 2007 12:34 AM, Peter Marks <petertmarks@gmail.com> wrote:
> I am trying to assemble an array of month names called
> "names_of_months_paid":
>
> 0 first_month_paid = client.first_month_paid
> 1 names_of_months_paid = []
> 2 number_of_months_paid.times do
> 3 names_of_months_paid << first_month_paid.strftime("%B")
> 4 first_month_paid >> (1)
> 5 end
>
> For each payment ("number_of_months_paid"), I need to store the name of
> the month, then store the name of the next month starting from
> "first_month_paid". I seem to be having trouble advancing the month of
> "first_month_paid" on line 4 as I am left with an array of first month
> names. How might I get this to work?
> --
> Posted via http://www.ruby-....
>
>
irb(main):020:0> t=Time::now
=> Wed Nov 28 11:50:38 +0100 2007
irb(main):021:0> t.month
=> 11
irb(main):022:0> Date::MONTHNAMES[t.month]
=> "November"
irb(main):023:0> m = 12
=> 12
irb(main):024:0> Date::MONTHNAMES[(m % 12 ).succ]
=> "January"
irb(main):025:0> m = 1
=> 1
irb(main):026:0> Date::MONTHNAMES[(m % 12 ).succ]
=> "February"

HTH
Robert


--

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---
All truth passes through three stages. First, it is ridiculed. Second,
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Peter Marks

11/28/2007 7:42:00 PM

0

Thanks for your suggestions Robert. Looks like this is all I needed to
do:

4 first_month_paid = first_month_paid >> (1)
--
Posted via http://www.ruby-....