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comp.lang.ruby

Noobie question: saving the values

Druhie Almighty

9/29/2007 11:28:00 AM

May you forgive me for this irrelevant thread but nonetheless, I need
your help.
I'm new at programming and recently I've faced with the problem
connected with the peculiarity of Ruby. Unlike many other languages, the
variables in it contain not the objects themselves but only links to
them, right?
So can you please explain me why do these two operations very close to
each other result in different ways, considering the fact that both a
and b contain the same link?

1)
a="13"
b=a
a="12"
puts b --> 13

2)
a="13"
b=a
a[1]="2"
puts b --> 12

To be more exact, in my program I need an array and a
variable=method(array). But when I call the method, the array itself
changes as well. How do I save the value of the array and get the
neccesary value of the variable at the same time?
P.S. And yes, I sought for solution in a guide but so far haven't found
anything.
--
Posted via http://www.ruby-....
2 Answers

David A. Black

9/29/2007 11:35:00 AM

0

Druhie Almighty

9/29/2007 12:13:00 PM

0

Thanks for your quick help, looks like I'm starting to understand
something and the program to be done by tomorrow works properly at last
:)
I hope you don't mind if I come again with a couple of another newbie's
questions? :)
Thanks a lot once again.
--
Posted via http://www.ruby-....