Phrogz
9/25/2007 2:52:00 PM
On Sep 24, 6:31 pm, barjunk <barj...@attglobal.net> wrote:
> I'm having to sort some IP addresses that are stored in a hash. I
> came up with the code below to accomplish the task. I have two
> questions:
>
> - What if any is a better way to have done this?
> - Given that the hash has to be the mac address, could I store the
> hash values in a different way to make this easier?
>
> require 'ipaddr'
>
> hash={}
> hash["00:19:d2:7b:55:10"]=["c","12.12.19.11",3]
> hash["00:18:39:0d:a1:e9"]=["b","12.12.19.83",1]
> hash["00:11:50:18:0c:0e"]=["a","12.12.19.81",2]
>
> #the second index is the value item to sort by.
> #this particular sort would fail if [1][1] was not an IP address
>
> sortedarray = hash.sort { |a,b|
> IPAddr.new(a[1][1]).to_i <=> IPAddr.new(b[1][1]).to_i
>
> }
>
> sortedarray.each { |item|
>
> print "mac:", item[0] + "\n"
> print "IP:", item[1][1] + "\n"
>
> }
# May not be faster, but doesn't rely on the ipaddr library
hash={}
hash["00:19:d2:7b:55:10"]=["c","1.12.19.11",3]
hash["00:18:39:0d:a1:e9"]=["b","12.12.19.83",1]
hash["00:11:50:18:0c:0e"]=["a","12.12.19.81",2]
hash["00:00:00:08:c3:1e"]=["a","2.12.19.81",2]
hash["fe:00:00:08:c6:2f"]=["a","204.12.19.81",2]
sorted_array = hash.sort_by{ |mac, settings|
# Break the IP into an array of integers
# sort_by will sort by the first entry first, then the second, and
so on
settings[1].split('.').map{ |digits| digits.to_i }
}
# Note that you can break apart the array of arrays in the iteration
# And use puts and string interpolation for simpler printing
sorted_array.each { |mac, settings|
puts "mac: #{mac}"
puts "IP: #{settings[1]}"
}