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comp.lang.ruby

range object as a parameter

Josselin

5/28/2007 6:04:00 PM

I trying to use a range object from an array of ranges objects as a parameter


my_range = [(0..2), (2..5), (5..10), (10..15), (15..25)]

props = []
domains = Domain.find(:all)
# keep track of the number of domains
@ props[0] = domains.nitems
k = params[:id] # can be 0, 1 ,2,3,4

1.step(domains.nitems,1) do |d|
props[d] = Proposition.find_by_range( ( my_range[k ] ) , ......... )
d = d.next
end

I got an error : can't convert String into Integer in the line :
props[d] = Proposition.find_by_range( ( my_range[k ] ) , ......... )

is is wrong ?

thanks for your help

joss
2 Answers

Alex Young

5/28/2007 6:10:00 PM

0

Josselin wrote:
> I trying to use a range object from an array of ranges objects as a
> parameter
>
>
> my_range = [(0..2), (2..5), (5..10), (10..15), (15..25)]
>
> props = []
> domains = Domain.find(:all)
> # keep track of the number of domains
> @ props[0] = domains.nitems
> k = params[:id] # can be 0, 1 ,2,3,4
>
> 1.step(domains.nitems,1) do |d|
> props[d] = Proposition.find_by_range( ( my_range[k ] ) , ......... )
> d = d.next
> end
>
> I got an error : can't convert String into Integer in the line :
> props[d] = Proposition.find_by_range( ( my_range[k ] ) , ......... )
>
> is is wrong ?
Here's a guess: k is a String? Array indices can only be Integers -
try my_range[k.to_i].

--
Alex

Josselin

5/28/2007 8:24:00 PM

0

On 2007-05-28 20:09:43 +0200, Alex Young <alex@blackkettle.org> said:

> Josselin wrote:
>> I trying to use a range object from an array of ranges objects as a parameter
>>
>>
>> my_range = [(0..2), (2..5), (5..10), (10..15), (15..25)]
>>
>> props = []
>> domains = Domain.find(:all)
>> # keep track of the number of domains
>> @ props[0] = domains.nitems
>> k = params[:id] # can be 0, 1 ,2,3,4
>>
>> 1.step(domains.nitems,1) do |d|
>> props[d] = Proposition.find_by_range( ( my_range[k ] ) , ......... )
>> d = d.next
>> end
>>
>> I got an error : can't convert String into Integer in the line :
>> props[d] = Proposition.find_by_range( ( my_range[k ] ) , ......... )
>>
>> is is wrong ?
> Here's a guess: k is a String? Array indices can only be Integers -
> try my_range[k.to_i].

thanks that's it... I was not searching for the right problem... could
not find the right solution...

4 years better than 2... don't know why we have been created like that
! (or "evolutionned"....... ;-)))