Trans
2/2/2007 1:53:00 PM
On Feb 1, 11:30 pm, "Chris Shea" <cms...@gmail.com> wrote:
> On Feb 1, 9:20 pm, "Trans" <transf...@gmail.com> wrote:
>
>
>
> > On Feb 1, 11:10 pm, "Chris Shea" <cms...@gmail.com> wrote:
>
> > > I have a vacuum fluorescent display in my office, and I've been
> > > messing around with it. Now that I've figured out how to communicate
> > > with the serial connection it's time for some fun. Its shortcoming is
> > > its 2 lines of 20 chars. So I naturally wrote a fortune cookie program
> > > for it.
>
> > > I want to make adding new fortunes easy (and without having to figure
> > > out myself where to force a line break), so I basically need to split
> > > a string (approximately) in half at a word boundary. This is what I
> > > have:
>
> > > class String
> > > def halve
> > > first_half = ''
> > > second_half = self
> > > until first_half.length >= length / 2
> > > match = / /.match(second_half)
> > > first_half << match.pre_match << ' '
> > > second_half = match.post_match
> > > end
> > > [first_half.strip, second_half]
> > > end
> > > end
>
> > > I have a feeling there's a one-line regexp that can do this. Am I
> > > right? If not, is there a better way?
>
> > untested but...
>
> > i = [0..str.size / 2].index(' ')
> > first_half, second_half = str[0...i], str[i..-1].strip
>
> > however, you might just prefer
>
> > require 'facets/core/string/word_wrap'
> > str.word_wrap(20)
>
> > T.
>
> Tested, and failed. The index returns the position of the very first
> space. (Also, it would have to be str[0..(str.size / 2)].index(' ')
> but, still, it's no good).
ah, size/2 has to be added to i, then it works.
> Word wrapping is wrong for the occasion, as I'd like to split even
> lines less than 20 chars, and have them of approximately equal length.
not sure i understand, the size can be set, for example:
word_wrap(str.size/2)
t.