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comp.lang.ruby

Hash & keys...

Sébastien Wautelet

10/13/2006 12:06:00 AM

I'm having some trouble understanding how hashes work in Ruby. Consider
the following test :

irb(main):002:0> v=Vector[4,5]
=> Vector[4, 5]
irb(main):003:0> v2=Vector[4,5]
=> Vector[4, 5]
irb(main):004:0> v==v2
=> true
irb(main):005:0> v.hash
=> 17
irb(main):006:0> v2.hash
=> 17
irb(main):007:0> h=Hash.new
=> {}
irb(main):008:0> h[v]="whatever is in (4,5)"
=> "whatever is in (4,5)"
irb(main):009:0> h[v2]
=> nil

I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both
have the same hash value... what am I doing wrong?

--
Posted via http://www.ruby-....

7 Answers

Tim Hunter

10/13/2006 12:19:00 AM

0

Sébastien Wautelet wrote:
> I'm having some trouble understanding how hashes work in Ruby. Consider
> the following test :
>
> irb(main):002:0> v=Vector[4,5]
> => Vector[4, 5]
> irb(main):003:0> v2=Vector[4,5]
> => Vector[4, 5]
> irb(main):004:0> v==v2
> => true
> irb(main):005:0> v.hash
> => 17
> irb(main):006:0> v2.hash
> => 17
> irb(main):007:0> h=Hash.new
> => {}
> irb(main):008:0> h[v]="whatever is in (4,5)"
> => "whatever is in (4,5)"
> irb(main):009:0> h[v2]
> => nil
>
> I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both
> have the same hash value... what am I doing wrong?
>
>
It's not enough that they have the same hash value or that obj1 == obj2.
For the purposes of Hash, two objects are the same if obj1.eql?(obj2).
Does v1.eql?(v2)?



Daniel Waite

10/13/2006 12:28:00 AM

0

Sébastien Wautelet wrote:
> I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both
> have the same hash value... what am I doing wrong?

Hash keys can be any object. So your hash, h, has one key, the object v.

Take another hash real quick, we'll call it hash.

hash = Hash.new

hash['rabbit'] = 'cute' # 'cute'
hash['blue'] # nil

The value for any hash key not defined is nil (unless you explicitly
tell the hash during instantiation to use another value).

So just because you're using the value of v as a key in your hash, does
not mean that v2 is automatically another key in your hash.

--
Posted via http://www.ruby-....

Daniel Waite

10/13/2006 12:36:00 AM

0

I think you're getting hung up on this part:

Sébastien Wautelet wrote:
> irb(main):004:0> v==v2
> => true

Yes, v and v2 are equal. But that is irrelevant with regards to your
hash.

Now, if you had to objects that were identical (not equal, but
identical) then it would work:

s1 = 'string'
s2 = s1

h = Hash.new

h[s1] # 'string'
h[s2] # 'string'

s1.upcase!

h[s2] # 'STRING'
h[s1] # 'STRING'

Hope that helps.

--
Posted via http://www.ruby-....

Kenneth McDonald

10/13/2006 4:50:00 AM

0

Timothy Hunter wrote:
> Sébastien Wautelet wrote:
>> I'm having some trouble understanding how hashes work in Ruby.
>> Consider the following test :
>>
>> irb(main):002:0> v=Vector[4,5]
>> => Vector[4, 5]
>> irb(main):003:0> v2=Vector[4,5]
>> => Vector[4, 5]
>> irb(main):004:0> v==v2
>> => true
>> irb(main):005:0> v.hash
>> => 17
>> irb(main):006:0> v2.hash
>> => 17
>> irb(main):007:0> h=Hash.new
>> => {}
>> irb(main):008:0> h[v]="whatever is in (4,5)"
>> => "whatever is in (4,5)"
>> irb(main):009:0> h[v2]
>> => nil
>>
>> I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and
>> both have the same hash value... what am I doing wrong?
>>
>>
> It's not enough that they have the same hash value or that obj1 ==
> obj2. For the purposes of Hash, two objects are the same if
> obj1.eql?(obj2). Does v1.eql?(v2)?
>
>
Testing reveals that they don't. but that strikes me as a bug in the
Vector class. It violates the guidelines given in the PickAxe book
(bottom of page 568), and more importantly, it violates common
intuition. If two vectors that are created in exactly the same manner
aren't eql?, they're useless for use as hash keys. I'd say file a bug
report, or at least a problem, on this one.

Cheers,
Ken



Gavin Kistner

10/13/2006 5:11:00 AM

0

Daniel Waite wrote:
> I think you're getting hung up on this part:
>
> Sébastien Wautelet wrote:
> > irb(main):004:0> v==v2
> > => true
>
> Yes, v and v2 are equal. But that is irrelevant with regards to your
> hash.
>
> Now, if you had to objects that were identical (not equal, but
> identical) then it would work:

I think it is relevant, given that the Vector class is designed to be
immutable. I would agree that the Vector class should probably define
#eql? as an alias for #==.

Rick DeNatale

10/13/2006 2:55:00 PM

0

On 10/13/06, Phrogz <gavin@refinery.com> wrote:

> I think it is relevant, given that the Vector class is designed to be
> immutable. I would agree that the Vector class should probably define
> #eql? as an alias for #==.

It appears to be a typo in Matrix.rb - This is in ruby1.8.4:

class Vector
...
#
# Returns +true+ iff the two vectors have the same elements in the same order.
#
def ==(other)
return false unless Vector === other

other.compare_by(@elements)
end
alias eqn? ==
~~~

And Vector seems to be the only implementor of eqn?

rick@frodo:~/ruby-1.8.4$ ri eqn
------------------------------------------------------------ Vector#eqn?
eqn?(other)
------------------------------------------------------------------------
Alias for #==

And it's not yet fixed in 1.9
rick@frodo:~/ruby-1.8.4$ grep eqn /public/rubysource/ruby1.9/ruby/lib/matrix.rb
alias eqn? ==



--
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denh...

bbfanbb

10/22/2008 6:20:00 PM

0


<bmoore@nyx.net> wrote in message
news:061754fb-71d5-4eb2-868c-a442e526428c@c36g2000prc.googlegroups.com...
On Oct 22, 9:59 am, acd <po...@manlymail.net> wrote:
> http://i55.photobucket.com/albums/g128/davidbellel/david2/j...
>
> Yes, it's a safe bet Sabathia will not end up in Boston.
>
> And you wonder why so many Red Sox fans and haters of Yankees such as,
> oh.. Paul O'Neil, for example, are so terrified of Obama's impending
> election.
>
> L O L

You think one guy with a sign is meaningful? That's silly.

Black (non-Hispanic) MLB players in general are at an all time low.
It's not a Red Sox thing. Cleveland had only Sabathia one year
recently. Atlanta and Houston have had none, including the year the
Astros went to the WS.

Is it not the best players that make teams not best color? This isnt' 1960
anymore