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comp.lang.ruby

Re: match with string instead of regexp fails

Cameron, Gemma (UK)

10/12/2006 10:53:00 AM


I thought the syntax was incorrect....

"cat" =~ "a" #=> 1

Fails as it's looking to match a reg ex not a string.

Should be:

"cat" =~ /a/ #=> 1

Or am I wrong?!?!

Gem



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1 Answer

Jano Svitok

10/12/2006 9:43:00 PM

0

On 10/12/06, Cameron, Gemma (UK) <Gemma.Cameron@baesystems.com> wrote:
>
> I thought the syntax was incorrect....
>
> "cat" =~ "a" #=> 1
>
> Fails as it's looking to match a reg ex not a string.
>
> Should be:
>
> "cat" =~ /a/ #=> 1
>
> Or am I wrong?!?!

Indeed, the example *is* wrong (judged by current ruby). However the
documentation states that:

str =~ obj => fixnum or nil

Match—<snip> If obj is a String, look for it in str (similar to
String#index). Returns the position the match starts, or nil if there
is no match. Otherwise, invokes obj.=~, passing str as an argument.
The default =~ in Object returns false.

"cat o' 9 tails" =~ '\d' #=> nil
<snip>
(http://ruby-doc.org/core/classes/String.ht...)

The question was why it doesn't work. The answer: the online
documentation is outdated (I don't know how the docs in the install
package look like, I haven't installed 1.8.5 yet).