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comp.lang.ruby

Re: Printing why's (poignant) guide to ruby

Kloubakov, Yura

2/14/2005 4:48:00 PM


> -----Original Message-----
> From: Ruth A. Kramer [mailto:rhkramer@fast.net]
> Sent: Monday, February 14, 2005 11:14
>
> Probably, but a = a + 1 was confusing for me when I first started
> programming (30+ years ago) (solving for a gives a = 1/2 ;-)
>
> Of course, I learned algebra a long time ago also, maybe today the

I've learned algebra a long time ago too, but don't think there is
a solution for 'a' in this equation :)

Yura.
3 Answers

Alexander Kellett

2/14/2005 4:56:00 PM

0

On Feb 14, 2005, at 5:48 PM, Kloubakov, Yura wrote:
>
>> -----Original Message-----
>> From: Ruth A. Kramer [mailto:rhkramer@fast.net]
>> Sent: Monday, February 14, 2005 11:14
>>
>> Probably, but a = a + 1 was confusing for me when I first started
>> programming (30+ years ago) (solving for a gives a = 1/2 ;-)
>>
>> Of course, I learned algebra a long time ago also, maybe today the
>
> I've learned algebra a long time ago too, but don't think there is
> a solution for 'a' in this equation :)

1 = 1 + 1/a
0 = 1/a
0*a = 1
0 = 1 (or the much easier a - a = 1, 0 = 1, but thats more
obviously stupid :P)

but thats obvious ain't it? ;)

Martin DeMello

2/14/2005 5:17:00 PM

0

Kloubakov, Yura <YKloubakov@ftxs.fujitsu.com> wrote:
> > From: Ruth A. Kramer [mailto:rhkramer@fast.net]
> > Sent: Monday, February 14, 2005 11:14
> >
> > Probably, but a = a + 1 was confusing for me when I first started
> > programming (30+ years ago) (solving for a gives a = 1/2 ;-)
> >
> > Of course, I learned algebra a long time ago also, maybe today the
>
> I've learned algebra a long time ago too, but don't think there is
> a solution for 'a' in this equation :)

irb(main):001:0> a = 1.0/0
=> Infinity
irb(main):002:0> a == (a+1)
=> true

"D".intern

martin

Caio Tiago Oliveira

2/14/2005 6:32:00 PM

0

Martin DeMello, 14/2/2005 14:19:
> Kloubakov, Yura <YKloubakov@ftxs.fujitsu.com> wrote:
>> > From: Ruth A. Kramer [mailto:rhkramer@fast.net]
>> > Sent: Monday, February 14, 2005 11:14
>> >
>> > Probably, but a = a + 1 was confusing for me when I first started
>> > programming (30+ years ago) (solving for a gives a = 1/2 ;-)
>> >
>> > Of course, I learned algebra a long time ago also, maybe today the
>>
>> I've learned algebra a long time ago too, but don't think there is
>> a solution for 'a' in this equation :)
>
> irb(main):001:0> a = 1.0/0
> => Infinity
> irb(main):002:0> a == (a+1)
> => true


Jokers guys.

a = a + 1

it's only one variable to one equation.
I've learned that we can do that.

a = ((5^(1/2) +- 1)/2)


:D

We can do that with algebra, but don't with Ruby.