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Markov chains...
aminer
5/21/2014 11:07:00 PM
Hello,
I have come to an interresting subject...
As you have noticed i have implemented a parallel conjugate gradient
solver, here it is:
https://sites.google.com/site/aminer68/parallel-implementation-of-conjugate-gradient-linear-sys...
This parallel solver is useful in mathematical finite elements
calculations etc.
but it is also useful in mathematical calculations of Markov chains...
Mathematical eigenvectors shows in phemenons that will exhibit a stable
behavior with time... and in Markov chains we searh also for
an eigenvector where the systeme will stabilize so we have to resolve:
A*vecteur(v) = 1*vecteur(v)
A is the transition matrix
and v a vector.
So since the Eigenvalue is 1 that means we have to solve the
following system of equationa that will give you the eigenvector
where the system will stabilize its behavior:
(A - I)*vecteur(x)= vector(0)
I is the indentity matrix.
And you can solve this system of equations by
my parallel conjugate gradient system solver also..
or you can solve the following system of equations:
(Transpose(A) - I)*vecteur(x)= vector(0)
And you can solve this system of equations by
my parallel conjugate gradient system solver also..
Thank you,
Amine Moulay Ramdane.
1 Answer
aminer
5/21/2014 11:13:00 PM
0
On 5/21/2014 4:07 PM, aminer wrote:
>
> Hello,
>
>
> I have come to an interresting subject...
>
>
> As you have noticed i have implemented a parallel conjugate gradient
> solver, here it is:
>
>
https://sites.google.com/site/aminer68/parallel-implementation-of-conjugate-gradient-linear-sys...
>
>
>
> This parallel solver is useful in mathematical finite elements
> calculations etc.
>
> but it is also useful in mathematical calculations of Markov chains...
>
>
> Mathematical eigenvectors shows in phemenons that will exhibit a stable
> behavior with time... and in Markov chains we searh also for
> an eigenvector where the systeme will stabilize so we have to resolve:
>
> A*vecteur(v) = 1*vecteur(v)
vecteur in french means vector.
>
> A is the transition matrix
> and v a vector.
>
>
> So since the Eigenvalue is 1 that means we have to solve the
> following system of equationa that will give you the eigenvector
> where the system will stabilize its behavior:
>
> (A - I)*vecteur(x)= vector(0)
>
> I is the indentity matrix.
>
> And you can solve this system of equations by
> my parallel conjugate gradient system solver also..
>
> or you can solve the following system of equations:
> (Transpose(A) - I)*vecteur(x)= vector(0)
>
>
> And you can solve this system of equations by
> my parallel conjugate gradient system solver also..
>
>
>
> Thank you,
> Amine Moulay Ramdane.
>
>
>
>
>
>
>
>
>
>
>
>
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