T. Onoma
11/12/2003 1:08:00 PM
> It's just the way it's representing the output. I think you'll find
> that the behavior (loading and unloading the YAML representation) is
> fine.
no, there must be something wrong because Kernel#y is doing almost exactly the same thing as Kernel#p and what would be the point of that?........
DOH! i just found out what it is: #y #to_yamls on its own. i was yamling a yaml! yoops. :)
my bad.